2022智慧上进英语二答案

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【参考范文】Dear Mike,I am delighted to tell you something about the summer camp with the theme of Exercise and Health.Beforegetting involved in it,I hardly ever felt well,either physically or mentally.However,things changed for thebetter in the camp.All the participants were required to exercise every day,including variety of sports,such asplaying table tennis,badminton and running.Besides,we are required to routinely keep a balanced diet,whichenabled me to feel energetic and get refreshed.Through the activity,not only have I gained an awareness of living a healthy life,but also enhanced thequality of my study as well as life.Best wishes！Yours sincerely,Li Hua

38.(12分,除标注外,每空2分)(1)统计学(1分)(2)Aa=7:1A对a完全显性、受精卵都能发育成子代、子代个体数量足够多(合理即给分)(3)圆形:三角形=3:11/15AaBb、Aabb、aaBb(不全不给分)11/12(1分)【解析】(1)对该种植物进行杂交实验时,应对子代的表现型进行记录,并对实验结果进行统计学分析。(2)若为一对等位基因控制,则A:aa=15:1,雌配子中Aa=1:1,设雄配子A占比为m,a占比为(1-m), A aa=mAA+mAa+(l-m)Aa(m)aa=15:1,解出m=7/8,因此F1植株产生的具有受精能力的雄配子基因型及比例是A:a=7:1,出现15:1需要满足的条件有受精卵都可以发育成个体,子代数量足够多,A对a完全显性等。(3)若假设Ⅱ成立,A/a、B/b位于两对同源染色体上,遵循基因自由组合定律,F1基因型为AaBb,测交后基因型为AaBb:aaBb:Aabb:aabb=1:1l:1,只有aabb是三角形,测交后代表现型比例为圆形:三角形=3:1,因为F1只有圆形,亲本基因型为AABB×aabb,圆形中和亲本基因型相同的只有1/15,F2中后代可以发生性状分离的基因型有AaBb、Aabb、aBb三种;F2中自交可以产生三角果实的有4/15AaBb、2/15Aabb、2/15aBb,自交产生的后代中三角形果实所占比例为4/15×1/16+/15×1/4+2/15×1/4=1/12,圆形果实为11/12。